Percentages for SSC, RRB & Banking exams 2026: 10 question models, formulas, shortcuts, solved examples, practice set with answers and a 7-day plan.
Percentages for SSC, RRB & Banking Exams 2026
Formulas, Shortcuts, 10 Question Models, Solved Examples & Practice Set
Ask any topper from a Hyderabad or Vijayawada coaching batch which chapter they finished first, and most will say the same thing: percentages. This post on Percentages for SSC, RRB & Banking Exams 2026 is built the way I wish someone had taught me: one question model at a time, with the shortcut, two or three worked examples and two exam-style questions for each model. In Telugu we call it shatam (เฐถాเฐคం), which literally points to "out of hundred", and that one idea is enough to crack almost every question below. Profit and loss, simple and compound interest, data interpretation and ratio questions all lean on it, so time spent here pays back across the whole quant paper.
Why Percentages Matter in SSC, RRB & Banking Exams
Percentages rarely come as just one or two "direct" questions. They hide inside profit-loss, interest, ratio, mixture and almost every data interpretation set. The quant section size below is from the standard exam patterns; the percentage share is our rough estimate from practice papers, so treat it as approx. only.
| Exam | Maths / Quant questions in the paper | Percentage weightage (approx.) |
|---|---|---|
| SSC CGL Tier-I | 25 | Approx. 1–3 direct, more inside profit-loss, interest and DI |
| SSC CHSL Tier-I | 25 | Approx. 1–3 direct, plus indirect use |
| RRB NTPC CBT-1 | 30 | Approx. 2–3 direct, plus indirect use |
| RRB Group D CBT | 25 | Approx. 2–3 direct, plus indirect use |
| IBPS PO / Clerk Prelims | 35 | Approx. 2–3 arithmetic, and the base for most DI sets |
The simple rule: if your percentage calculation is fast, half of your arithmetic and DI becomes easier.
Percentage Basics: The Core Concept
A percentage is just a fraction with 100 at the bottom. When someone says 18%, read it as 18 out of every 100, or 18/100. That is all. Three forms of the same question keep repeating:
- x% of N = (x × N) / 100
- A is what % of B = (A / B) × 100
- Percentage change = (Change / Original value) × 100. Always divide by the original value, never the new one.
Fraction to Percentage Table (memorise this)
If you know these by heart, you will convert most questions to simple fractions in your head. We built this table ourselves; the mixed form is the one examiners love.
| Fraction | Percentage | Fraction | Percentage |
|---|---|---|---|
| 1/2 | 50% | 1/11 | 9 1/11% (9.09%) |
| 1/3 | 33 1/3% (33.33%) | 1/12 | 8 1/3% (8.33%) |
| 1/4 | 25% | 1/13 | 7 9/13% (7.69%) |
| 1/5 | 20% | 1/14 | 7 1/7% (7.14%) |
| 1/6 | 16 2/3% (16.67%) | 1/15 | 6 2/3% (6.67%) |
| 1/7 | 14 2/7% (14.29%) | 1/16 | 6 1/4% (6.25%) |
| 1/8 | 12 1/2% (12.5%) | 1/17 | 5 15/17% (5.88%) |
| 1/9 | 11 1/9% (11.11%) | 1/18 | 5 5/9% (5.56%) |
| 1/10 | 10% | 1/19 and 1/20 | 5 5/19% (5.26%) and 5% |
Bonus: 3/8 = 37.5%, 5/8 = 62.5%, 7/8 = 87.5%, 2/3 = 66 2/3%, 3/4 = 75%, 5/6 = 83 1/3%. Multiples follow the same logic: 3/7 is 3 × 14 2/7 = 42 6/7%.
Key Percentage Formulas at a Glance
| Situation | Formula |
|---|---|
| Increase by r% | New value = Original × (100 + r) / 100 |
| Decrease by r% | New value = Original × (100 − r) / 100 |
| Successive change a% and b% | Net change = a + b + (a × b)/100 (use minus sign for a decrease) |
| Population growth at r% for n years | P × (1 + r/100)n |
| Depreciation at r% for n years | V × (1 − r/100)n |
| Price rises r%, keep expenditure same | Cut consumption by r / (100 + r) × 100 % |
| Price falls r%, keep expenditure same | Raise consumption by r / (100 − r) × 100 % |
| Expenditure = Price × Consumption | Use successive change on price% and consumption% |
| Percentage of percentage | a% of b% of N = (a × b × N) / 10,000 |
| Elections (2 candidates) | Winning margin = (Winner% − Loser%) of valid votes |
| Marks / pass-fail | Difference in % = difference in marks (between two students) |
| Income − Expenditure = Savings | Work with income as 100 and track each part |
| A is r% more than B | B is r / (100 + r) × 100 % less than A |
| A is r% less than B | B is r / (100 − r) × 100 % more than A |
Percentage Question Models for SSC, RRB & Banking 2026
Below are the 10 models that cover nearly every percentage question you will face. Do one model per sitting: read the idea, try the examples yourself first, then check the steps.
Model 1: Basic Percentage of a Number
This is the warm-up model, but speed here decides your overall speed. Break any percentage into easy blocks: 10% (move the decimal one place), 5% (half of 10%), 1% (move two places).
Example 1 Easy
Find 35% of 640.
- 10% of 640 = 64, so 30% = 192.
- 5% = half of 64 = 32.
- 35% = 192 + 32 = 224.
Answer: 224
Example 2 Easy
48 is what percent of 160?
- (48 / 160) × 100.
- 48/160 = 3/10.
- 3/10 × 100 = 30.
Answer: 30%
Example 3 Medium
Find 17% of 360 without a pen-and-paper multiplication.
- 10% = 36, 5% = 18, 2% = 7.2.
- 17% = 36 + 18 + 7.2.
Answer: 61.2
Find the value of 24% of 75 + 75% of 24.
(a) 18 (b) 24 (c) 36 (d) 48
Solution: 24% of 75 = 75% of 24 = 18 (swap rule). So the sum = 18 + 18 = 36. Answer: (c) 36
400 g is what percent of 2.5 kg?
(a) 1.6% (b) 16% (c) 25% (d) 62.5%
Solution: Convert to the same unit: 2.5 kg = 2,500 g. (400 / 2,500) × 100 = 16. Answer: (b) 16%
Model 2: Percentage Increase and Decrease
When a value goes up or down by a percent, multiply by a single factor instead of finding the change separately. A 15% rise means × 1.15; a 15% fall means × 0.85. To go back to the original, divide by that factor.
Example 4 Easy
Ramesh earns ₹28,000 a month. He gets a 15% raise. What is his new salary?
- New salary = 28,000 × 1.15.
- 28,000 × 0.15 = 4,200, add it to 28,000.
Answer: ₹32,200
Example 5 Easy
When a number is increased by 20%, it becomes 540. Find the number.
- Number × 6/5 = 540.
- Number = 540 × 5/6 = 450.
Answer: 450
Example 6 Medium
After a 12.5% increase, a value is 720. What was it originally?
- 12.5% = 1/8, so the new value is 9/8 of the original.
- Original = 720 × 8/9 = 640.
Answer: 640
A number decreased by 15% becomes 595. What is the number?
(a) 650 (b) 680 (c) 700 (d) 720
Solution: Number × 0.85 = 595. Number = 595 / 0.85 = 700. Answer: (c) 700
A shop's monthly sales went up from ₹48,000 to ₹54,000. Find the percentage increase.
(a) 11.1% (b) 12% (c) 12.5% (d) 13%
Solution: Increase = 6,000. (6,000 / 48,000) × 100 = 1/8 × 100 = 12.5. Answer: (c) 12.5%
Model 3: Successive Percentage Change
When two changes happen one after the other, the second change works on the new value, not the original. That is why 10% up and then 10% down does not bring you back to the start.
Example 7 Medium
The price of a phone is ₹15,000. It rises by 10% and then by 20%. Find the final price.
- Net change = 10 + 20 + (10 × 20)/100 = 32%.
- Final price = 15,000 × 1.32.
Answer: ₹19,800
Example 8 Medium
A shop gives two successive discounts of 20% and 10%. What single discount is equal to these?
- Net = −20 − 10 + (20 × 10)/100 = −28.
- So the single discount is 28% (not 30%).
Answer: 28%
Example 9 Medium
The length of a rectangle increases by 20% and its breadth decreases by 10%. What happens to the area?
- Area = length × breadth, so use successive change.
- 20 − 10 + (20 × −10)/100 = 20 − 10 − 2 = 8.
Answer: Area increases by 8%
The price of an article is first increased by 10% and then decreased by 10%. The net effect is:
(a) No change (b) 1% increase (c) 1% decrease (d) 2% decrease
Solution: Equal rise and fall: loss = 10²/100 = 1%. Answer: (c) 1% decrease
A jacket marked ₹2,000 gets three successive discounts of 10%, 20% and 25%. What is the selling price?
(a) ₹900 (b) ₹1,000 (c) ₹1,080 (d) ₹1,100
Solution: 2,000 × 0.9 = 1,800; × 0.8 = 1,440; × 0.75 = 1,080. Answer: (c) ₹1,080
Model 4: Population Growth and Depreciation
Population and value questions are successive change repeated every year. Growth multiplies by (1 + r/100) each year; depreciation multiplies by (1 − r/100). For a few years, just multiply step by step.
Example 10 Medium
The population of a town is 50,000. It grows by 8% every year. What will it be after 2 years?
- 2-year change = 16 + 0.64 = 16.64%.
- 50,000 × 1.1664.
Answer: 58,320
Example 11 Medium
A bike loses 10% of its value every year. Today, after 3 years, it is worth ₹72,900. What was its price 3 years ago?
- Value now = Original × 0.9 × 0.9 × 0.9 = Original × 0.729.
- Original = 72,900 / 0.729.
Answer: ₹1,00,000
Example 12 Hard
A village has 20,000 people. Population rises by 10% in the first year and falls by 10% in the second year. Find the population after 2 years.
- After year 1: 20,000 × 1.1 = 22,000.
- After year 2: 22,000 × 0.9 = 19,800.
Answer: 19,800
A machine worth ₹2,50,000 depreciates at 20% per year. What is its value after 2 years?
(a) ₹1,50,000 (b) ₹1,60,000 (c) ₹1,75,000 (d) ₹2,00,000
Solution: 2,50,000 × 0.8 × 0.8 = 2,50,000 × 0.64. Answer: (b) ₹1,60,000
The population of a village is 1,25,000 and it decreases by 4% every year. What will it be after 2 years?
(a) 1,15,000 (b) 1,15,200 (c) 1,16,000 (d) 1,20,000
Solution: 1,25,000 × 0.96 = 1,20,000. 1,20,000 × 0.96 = 1,15,200. Answer: (b) 1,15,200
Model 5: Price, Consumption and Expenditure
Expenditure = Price × Consumption. If price goes up and you want to spend the same amount, consumption must come down, and the cut is always smaller than the rise in percent terms.
Example 13 Easy
The price of rice rises by 25%. By how much percent should a family cut its rice use so that the monthly spend stays the same?
- Cut = 25 / (100 + 25) × 100.
- = 25/125 × 100 = 20.
Answer: 20%
Example 14 Hard
Sugar becomes 20% cheaper, so a person can buy 5 kg more for ₹600. What was the original price per kg?
- 20% of ₹600 = ₹120 is the money saved.
- That ₹120 buys the extra 5 kg, so the new price = ₹24/kg.
- New price = 80% of original, so original = 24 / 0.8 = 30.
- Check: 600/24 = 25 kg, 600/30 = 20 kg, difference 5 kg.
Answer: ₹30 per kg
Example 15 Medium
The price of a product rises by 20% and a family reduces its consumption by 10%. What is the change in their expenditure?
- Use successive change: 20 − 10 + (20 × −10)/100.
- = 20 − 10 − 2 = 8.
Answer: Expenditure rises by 8%
Petrol price rises by 20%. By what percent must a person reduce consumption to keep the expense unchanged?
(a) 16 2/3% (b) 20% (c) 25% (d) 18%
Solution: 20 / 120 × 100 = 1/6 × 100 = 16 2/3. Answer: (a) 16 2/3%
A 10% fall in the price of tea lets a buyer get 2 kg more for ₹1,800. Find the original price per kg.
(a) ₹90 (b) ₹95 (c) ₹100 (d) ₹110
Solution: 10% of 1,800 = 180, which buys 2 kg, so the new price = ₹90/kg. Original = 90 / 0.9 = 100. Answer: (c) ₹100
Model 6: Income, Expenditure and Savings
Take income as 100. Whatever is spent, the rest is savings. When income and spending change by different percents, find both new values and subtract; never just subtract the two percentages.
Example 16 Medium
Suresh spends 75% of his income. His income rises by 20% and his spending rises by 10%. By what percent do his savings rise?
- Income 100, spend 75, save 25.
- New income 120, new spend 82.5, new savings 37.5.
- Rise = 12.5 / 25 × 100 = 50.
Answer: 50%
Example 17 Easy
Lakshmi saves 20% of her salary. She saves ₹6,400 a month. How much does she spend?
- 20% of salary = 6,400, so salary = 32,000.
- Spending = 32,000 − 6,400.
Answer: ₹25,600
Example 18 Hard
A man spends 30% of his salary on rent and 25% of the remaining on food. He saves the rest, which is ₹21,000. What is his salary?
- After rent, 70% is left.
- Food = 25% of 70% = 17.5%, so 52.5% is left.
- 52.5% of salary = 21,000, so salary = 21,000 / 0.525.
Answer: ₹40,000
A person spends 80% of his income. His income goes up by 10% but his savings stay the same. By what percent did his spending increase?
(a) 10% (b) 12% (c) 12.5% (d) 15%
Solution: Income 100: spend 80, save 20. New income 110, savings 20, so spend 90. Increase = 10/80 × 100 = 12.5. Answer: (c) 12.5%
A woman spends 40% of her income on the house, 20% of the remainder on travel and 25% of what is left after that on her child's education. She saves ₹13,500. Find her income.
(a) ₹30,000 (b) ₹36,000 (c) ₹37,500 (d) ₹40,000
Solution: Left after house: 0.6; after travel: 0.6 × 0.8 = 0.48; after education: 0.48 × 0.75 = 0.36. Income = 13,500 / 0.36. Answer: (c) ₹37,500
Model 7: Marks and Pass-Fail
Pass marks are a fixed number. One student falls short of it, another crosses it. The gap between their percentages equals the gap between their marks, and that gives you the maximum marks directly.
Example 19 Medium
A student who scores 30% fails by 24 marks. Another student who scores 42% gets 36 marks more than the pass mark. Find the maximum marks and the pass mark.
- 42% − 30% = 12% of maximum = 24 + 36 = 60 marks.
- Maximum = 60 / 0.12 = 500.
- Pass mark = 30% of 500 + 24 = 150 + 24 = 174.
Answer: Maximum 500, pass mark 174
Example 20 Easy
To pass, a student needs 40% of the maximum marks. She scores 185 and fails by 35 marks. What are the maximum marks?
- Pass marks = 185 + 35 = 220.
- 40% of maximum = 220, so maximum = 220 / 0.4.
Answer: 550
A candidate needs 33% to pass. He scores 120 marks and fails by 12 marks. What are the maximum marks?
(a) 360 (b) 396 (c) 400 (d) 420
Solution: Pass marks = 120 + 12 = 132. Maximum = 132 / 0.33 = 400. Answer: (c) 400
Student A scores 35% and fails by 20 marks. Student B scores 45% and gets 30 marks more than the pass mark. Find the maximum marks.
(a) 400 (b) 450 (c) 500 (d) 550
Solution: 10% = 20 + 30 = 50 marks. Maximum = 50 × 10 = 500. Answer: (c) 500
Model 8: Elections and Votes
Read carefully: "votes polled", "valid votes" and "total voters" are three different numbers. First remove non-voters, then invalid votes, and only then apply the candidates' percentages.
Example 21 Medium
In an election between two candidates, 4% of votes polled were invalid. The winner got 58% of the valid votes and won by 4,800 votes. How many votes were polled?
- Margin = 58% − 42% = 16% of valid votes = 4,800.
- Valid votes = 4,800 / 0.16 = 30,000.
- Valid = 96% of polled, so polled = 30,000 / 0.96.
Answer: 31,250
Example 22 Easy
The losing candidate got 40% of the valid votes and lost by 6,300 votes. Find the total valid votes.
- Winner got 60%, so margin = 20% of valid votes.
- Valid votes = 6,300 / 0.2.
Answer: 31,500
Example 23 Hard
A town has 50,000 voters. 80% of them voted and 5% of those votes were invalid. The winner of a two-person contest got 55% of the valid votes. By how many votes did the winner win?
- Votes polled = 40,000; valid = 95% of 40,000 = 38,000.
- Winner = 20,900; loser = 17,100.
- Margin = 10% of 38,000.
Answer: 3,800 votes
In a two-candidate election, the winner gets 62% of the valid votes and wins by 9,600 votes. How many valid votes were cast?
(a) 32,000 (b) 36,000 (c) 40,000 (d) 48,000
Solution: Margin = 62 − 38 = 24% of valid votes. Valid = 9,600 / 0.24 = 40,000. Answer: (c) 40,000
A constituency has 25,000 voters. 10% did not vote and 10% of the votes cast were invalid. The winner got 60% of the valid votes. How many votes did the winner get?
(a) 12,150 (b) 12,500 (c) 13,500 (d) 15,000
Solution: Cast = 22,500; valid = 20,250. Winner = 60% of 20,250 = 12,150. Answer: (a) 12,150
Model 9: Mixtures and Alloys (Percentage Based)
In a mixture, one part usually stays fixed while the other is added or removed. Hold on to the part that does not change; its new percentage gives you the new total.
Example 24 Medium
A 40-litre mixture of milk and water has 25% water. How much water should be added so that water becomes 40%?
- Milk = 75% of 40 = 30 litres; milk does not change.
- In the new mix milk is 60%, so new total = 30 / 0.6 = 50 litres.
- Water to add = 50 − 40.
Answer: 10 litres
Example 25 Medium
A 60 kg alloy has 20% copper. How much pure copper must be added to make the copper share 25%?
- Non-copper metal = 80% of 60 = 48 kg (fixed).
- In the new alloy it is 75%, so new total = 48 / 0.75 = 64 kg.
- Copper to add = 64 − 60.
Answer: 4 kg
Example 26 Easy
30 litres of a 20% acid solution is mixed with 20 litres of a 45% acid solution. What is the acid percentage in the mix?
- Acid = 6 + 9 = 15 litres in 50 litres.
- 15/50 × 100.
Answer: 30%
A 60-litre mixture of milk and water has 10% water. How much water must be added to make the water 20%?
(a) 6 litres (b) 7.5 litres (c) 10 litres (d) 12 litres
Solution: Milk = 54 litres, which must be 80% of the new mix. New total = 54 / 0.8 = 67.5, so add 7.5 litres. Answer: (b) 7.5 litres
50 g of a sugar solution has 8% sugar. How much water must evaporate so that sugar becomes 10%?
(a) 5 g (b) 8 g (c) 10 g (d) 12 g
Solution: Sugar = 4 g (fixed). New total = 4 / 0.1 = 40 g, so 10 g of water must evaporate. Answer: (c) 10 g
Model 10: Percentage Comparison (A is x% more or less than B)
The base changes when you flip the comparison. If A is 25% more than B, then B is not 25% less than A, because now you divide by A, the bigger number.
Example 27 Medium
A's salary is 25% more than B's. By what percent is B's salary less than A's?
- Let B = 100, then A = 125.
- Difference 25 on base 125: 25/125 × 100 = 20.
Answer: 20%
Example 28 Medium
Kavya's income is 20% less than Ravi's. By what percent is Ravi's income more than Kavya's?
- Ravi = 100, Kavya = 80.
- Difference 20 on base 80: 20/80 × 100 = 25.
Answer: 25%
Example 29 Hard
A is 120% of B and B is 75% of C. What percent of C is A, and by what percent is C more than A?
- A = 1.2 × 0.75 × C = 0.9C, so A = 90% of C.
- C is 10 more on base 90: 10/90 × 100 = 11 1/9.
Answer: A = 90% of C; C is 11 1/9% more than A
x is 40% more than y. By what percent is y less than x?
(a) 28 4/7% (b) 30% (c) 33 1/3% (d) 40%
Solution: 40 / 140 × 100 = 2/7 × 100 = 28 4/7. Answer: (a) 28 4/7%
If 30% of A is equal to 45% of B, then A is what percent more than B?
(a) 15% (b) 33 1/3% (c) 50% (d) 150%
Solution: 0.3A = 0.45B, so A/B = 1.5. A is 50% more than B. Answer: (c) 50%
Practice Set: 10 Questions (Try Before Checking Answers)
- Find 18% of 750.
- A number increased by 35% becomes 810. Find the number.
- Find the single equivalent increase for two successive increases of 15% and 10%.
- Oil becomes 25% cheaper. By what percent can a family increase its oil use without spending more?
- A town has 64,000 people and grows at 5% a year. What will the population be after 2 years?
- Anil saves 15% of his income, which is ₹5,400. What is his income?
- The pass mark is 36%. A student scores 162 and fails by 18 marks. Find the maximum marks.
- In a two-candidate election, the winner got 56% of the valid votes and won by 2,880 votes. Find the total valid votes.
- 10 litres of water is added to 30 litres of a mixture that has 20% alcohol. What is the alcohol percentage now?
- The length of a rectangle goes up by 25% and its breadth goes down by 20%. What is the change in area?
Answer Key
| Q | Answer | Q | Answer |
|---|---|---|---|
| 1 | 135 | 6 | ₹36,000 |
| 2 | 600 | 7 | 500 |
| 3 | 26.5% | 8 | 24,000 |
| 4 | 33 1/3% | 9 | 15% |
| 5 | 70,560 | 10 | No change (0%) |
Common Mistakes Students Make in Percentages
- Dividing by the wrong base. Percentage change is always on the original value. "From 80 to 100" is a 25% rise, but "from 100 to 80" is a 20% fall.
- Adding successive percentages directly. 20% and 10% discounts are 28%, not 30%. Always use a + b + ab/100.
- Ignoring invalid votes or non-voters. Apply the winner's percentage only on valid votes.
- Mixing units. Convert kg to g, or hours to minutes, before you divide.
- Assuming a rise and an equal fall cancel out. They never do; there is always a small loss.
- Doing full multiplication when options are far apart. Use fractions and approximate; check the options first.
- Skipping the "check" step. In mixture and price questions, put your answer back into the question once. It takes five seconds and saves negative marks.
7-Day Percentage Practice Plan
| Day | What to do | Target |
|---|---|---|
| Day 1 | Learn the fraction table (1/2 to 1/20) and Model 1. Recite the table twice: morning and night. | 30 quick calculations in 15 minutes |
| Day 2 | Models 2 and 3: increase, decrease, successive change. | 20 questions, focus on the reverse (find original) type |
| Day 3 | Model 4 (population, depreciation) and Model 5 (price-consumption). | 20 questions |
| Day 4 | Models 6 and 7: income-savings and marks. | 20 questions, write the "income = 100" setup every time |
| Day 5 | Models 8, 9 and 10: elections, mixtures, comparison. | 20 questions |
| Day 6 | Mixed timed test of all 10 models. | 25 questions in 20 minutes |
| Day 7 | Revise mistakes from Day 6, then try percentage-based DI sets. | 2 DI sets + redo all wrong questions |
Percentages for SSC, RRB & Banking Exams – Frequently Asked Questions
What is percentage?
A percentage is a number written out of 100. The word comes from "per cent", meaning per hundred, so 45% simply means 45 out of 100, or 0.45.
How to calculate percentage of a number?
Multiply the number by the percentage and divide by 100. For example, 20% of 450 = (20 × 450) / 100 = 90. For quick mental work, find 10% first and build up from there.
How to calculate percentage of marks?
Divide the marks you scored by the total marks and multiply by 100. If you scored 432 out of 600, your percentage is (432 / 600) × 100 = 72%.
What is the formula of percentage?
Percentage = (Part / Whole) × 100. The same formula, turned around, gives Part = Percentage × Whole / 100 and Whole = Part × 100 / Percentage.
How to find percentage increase?
Percentage increase = (New value − Old value) / Old value × 100. If a price goes from ₹250 to ₹300, the increase is 50 / 250 × 100 = 20%.
How to find percentage decrease?
Percentage decrease = (Old value − New value) / Old value × 100. A fall from 300 to 255 is 45 / 300 × 100 = 15%. Always divide by the old (original) value.
How to convert a fraction to percentage?
Multiply the fraction by 100. So 3/8 = 3/8 × 100 = 37.5%. Learning the 1/2 to 1/20 table above makes most of these instant.
How to convert percentage to fraction or decimal?
Write the percentage over 100 and simplify, or move the decimal point two places to the left. 35% = 35/100 = 7/20 = 0.35.
What is the difference between percentage and percentage points?
Percentage points measure the plain gap between two percentages; percentage measures the relative change. If an interest rate moves from 8% to 10%, it rose by 2 percentage points, but by 25% in relative terms (2 / 8 × 100).
How to calculate discount percentage?
Discount % = (Marked price − Selling price) / Marked price × 100. A shirt marked ₹1,200 sold for ₹960 has a discount of 240 / 1,200 × 100 = 20%.
How to calculate profit percentage?
Profit % = Profit / Cost price × 100. If you buy something for ₹800 and sell it for ₹920, the profit is ₹120, so profit % = 120 / 800 × 100 = 15%. Profit is always on cost price, not selling price.
What is the shortcut for successive percentage change?
Use net change = a + b + (a × b) / 100, with a minus sign for any decrease. A 20% rise followed by a 20% fall gives 20 − 20 − 400/100 = −4%, so the value ends 4% lower, not unchanged.
How many questions come from percentages in SSC CGL?
Roughly 1 to 3 direct questions in the 25-question Tier-I maths section (approx. only; it changes from shift to shift). Percentages also sit inside profit-loss, interest and DI questions, so the real share is bigger.
What is the best way to practise percentages for exams?
Memorise the fraction table, then do 15 to 20 minutes of mixed questions every day instead of one long session. Time yourself, redo every wrong answer the next day, and follow the 7-day plan above before moving to DI sets.
Are the questions on this page from previous papers?
No. All examples and questions are written fresh by Nck115. The ones marked "PYQ-pattern" only follow the style of past papers.
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